# Combinations

Returns all combinations of a chosen amount of selected elements in the sequence.

## Source

```
/// <summary>
/// Returns all combinations of a chosen amount of selected elements in the sequence.
/// </summary>
/// <typeparam name = "T">The type of the elements of the input sequence.</typeparam>
/// <param name = "source">The source for this extension method.</param>
/// <param name = "select">The amount of elements to select for every combination.</param>
/// <param name = "repetition">True when repetition of elements is allowed.</param>
/// <returns>All combinations of a chosen amount of selected elements in the sequence.</returns>
public static IEnumerable<IEnumerable<T>> Combinations<T>( this IEnumerable<T> source, int select, bool repetition = false )
{
Contract.Requires( source != null );
Contract.Requires( select >= 0 );
return select == 0
? new[] { new T[0] }
: source.SelectMany( ( element, index ) =>
source
.Skip( repetition ? index : index + 1 )
.Combinations( select - 1, repetition )
.Select( c => new[] { element }.Concat( c ) ) );
}
```

## Example

```
int[] numbers = new[] { 0, 1 };
var result = numbers.Combinations( 2, true );
// result == {{0, 0}, {0, 1}, {1, 0}, {1, 1}}
```

Author: **Steven Jeuris**

Submitted on: **15 nov. 2011**

Language: **C#**

Type: **System.IEnumerable<T>**

Views: **8386**